2x^2+10x-1392=0

Solution for 2x^2+10x-1392=0 equation:

2x^2+10x-1392=0

a = 2; b = 10; c = -1392;
Δ = b2-4ac
Δ = 102-4·2·(-1392)
Δ = 11236
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{11236}=106$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-106}{2*2}=\frac{-116}{4}
=-29
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+106}{2*2}=\frac{96}{4}
=24
$